Faerie
VIP
Hi. I need help in Chemistry with Stoichiometry. My professor isn't the best and has assigned work that she hasn't taught before.
The question is....
13.33 cg of Barium Chloride is reacted with 135.2 mL of a 0.250 M sulfuric acid.
I balanced the equation
BaCl2(aq) + H2SO4(aq) --> BaSO4(s) + 2HCl(aq)
BaCl2 = A, H2SO4 = B, BaSO4 = C, HCl = D
I then converted 13.33cg A to grams of D (I got 4.667x10^-2 gHCl)
Then I converted 135.2mL B to grams of D (2.464x10^0 gHCl)
I found B to be the Limiting Reactant (LR)
I then converted from 135.2mL B to grams of C (7.888x10^0 gBaSO4)
Then, I took 135.2mL B to grams of A (7.039x10^0 gBaCl2)
I am stuck on how I find the remaining amount of BaCl2.
Also, I know it is original - reactant which I found to reactant when I went from B to A. I also converted 13.33cg A to g A (1.333x10^-1 gBaCl2)
How do I solve how much of BaCl2 is left over? Also, I'm pretty sure my previous calculations are right, but we use a specific PT when looking for molar mass so if you use a different one, your numbers might be off.
I think I solve it by taking the original which I believe to be the 1.333x10^-1 gBaCl2 and subtracting the reactant (7.039x10^0 gBaCl2) but I think this gives me a negative number and the answer cannot be negative.
The question is....
13.33 cg of Barium Chloride is reacted with 135.2 mL of a 0.250 M sulfuric acid.
I balanced the equation
BaCl2(aq) + H2SO4(aq) --> BaSO4(s) + 2HCl(aq)
BaCl2 = A, H2SO4 = B, BaSO4 = C, HCl = D
I then converted 13.33cg A to grams of D (I got 4.667x10^-2 gHCl)
Then I converted 135.2mL B to grams of D (2.464x10^0 gHCl)
I found B to be the Limiting Reactant (LR)
I then converted from 135.2mL B to grams of C (7.888x10^0 gBaSO4)
Then, I took 135.2mL B to grams of A (7.039x10^0 gBaCl2)
I am stuck on how I find the remaining amount of BaCl2.
Also, I know it is original - reactant which I found to reactant when I went from B to A. I also converted 13.33cg A to g A (1.333x10^-1 gBaCl2)
How do I solve how much of BaCl2 is left over? Also, I'm pretty sure my previous calculations are right, but we use a specific PT when looking for molar mass so if you use a different one, your numbers might be off.
I think I solve it by taking the original which I believe to be the 1.333x10^-1 gBaCl2 and subtracting the reactant (7.039x10^0 gBaCl2) but I think this gives me a negative number and the answer cannot be negative.